3.47 \(\int \frac {x}{\sinh ^{-1}(a x)} \, dx\)

Optimal. Leaf size=14 \[ \frac {\text {Shi}\left (2 \sinh ^{-1}(a x)\right )}{2 a^2} \]

[Out]

1/2*Shi(2*arcsinh(a*x))/a^2

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Rubi [A]  time = 0.04, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5669, 5448, 12, 3298} \[ \frac {\text {Shi}\left (2 \sinh ^{-1}(a x)\right )}{2 a^2} \]

Antiderivative was successfully verified.

[In]

Int[x/ArcSinh[a*x],x]

[Out]

SinhIntegral[2*ArcSinh[a*x]]/(2*a^2)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rule 5448

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int
[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n,
0] && IGtQ[p, 0]

Rule 5669

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[(a + b*x)^n*
Sinh[x]^m*Cosh[x], x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]

Rubi steps

\begin {align*} \int \frac {x}{\sinh ^{-1}(a x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\cosh (x) \sinh (x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{a^2}\\ &=\frac {\operatorname {Subst}\left (\int \frac {\sinh (2 x)}{2 x} \, dx,x,\sinh ^{-1}(a x)\right )}{a^2}\\ &=\frac {\operatorname {Subst}\left (\int \frac {\sinh (2 x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{2 a^2}\\ &=\frac {\text {Shi}\left (2 \sinh ^{-1}(a x)\right )}{2 a^2}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 14, normalized size = 1.00 \[ \frac {\text {Shi}\left (2 \sinh ^{-1}(a x)\right )}{2 a^2} \]

Antiderivative was successfully verified.

[In]

Integrate[x/ArcSinh[a*x],x]

[Out]

SinhIntegral[2*ArcSinh[a*x]]/(2*a^2)

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fricas [F]  time = 0.40, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {x}{\operatorname {arsinh}\left (a x\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/arcsinh(a*x),x, algorithm="fricas")

[Out]

integral(x/arcsinh(a*x), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{\operatorname {arsinh}\left (a x\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/arcsinh(a*x),x, algorithm="giac")

[Out]

integrate(x/arcsinh(a*x), x)

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maple [A]  time = 0.16, size = 13, normalized size = 0.93 \[ \frac {\Shi \left (2 \arcsinh \left (a x \right )\right )}{2 a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/arcsinh(a*x),x)

[Out]

1/2*Shi(2*arcsinh(a*x))/a^2

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{\operatorname {arsinh}\left (a x\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/arcsinh(a*x),x, algorithm="maxima")

[Out]

integrate(x/arcsinh(a*x), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.07 \[ \int \frac {x}{\mathrm {asinh}\left (a\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/asinh(a*x),x)

[Out]

int(x/asinh(a*x), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{\operatorname {asinh}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/asinh(a*x),x)

[Out]

Integral(x/asinh(a*x), x)

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